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20002442411111 is a prime number
BaseRepresentation
bin1001000110001001011100…
…11110010111110001100111
32121211012210121021211211112
410203010232132113301213
510110210000224123421
6110312554543255235
74133062112124656
oct443045636276147
977735717254745
1020002442411111
116411a96307716
1222b07355aa51b
13b212b72cb804
144d21a279b19d
1524a4994d845b
hex12312e797c67

20002442411111 has 2 divisors, whose sum is σ = 20002442411112. Its totient is φ = 20002442411110.

The previous prime is 20002442411069. The next prime is 20002442411113. The reversal of 20002442411111 is 11111424420002.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20002442411111 is a prime.

Together with 20002442411113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20002442411113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10001221205555 + 10001221205556.

It is an arithmetic number, because the mean of its divisors is an integer number (10001221205556).

Almost surely, 220002442411111 is an apocalyptic number.

20002442411111 is a deficient number, since it is larger than the sum of its proper divisors (1).

20002442411111 is an equidigital number, since it uses as much as digits as its factorization.

20002442411111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 20002442411111 its reverse (11111424420002), we get a palindrome (31113866831113).

The spelling of 20002442411111 in words is "twenty trillion, two billion, four hundred forty-two million, four hundred eleven thousand, one hundred eleven".