Base | Representation |
---|---|
bin | 11101000111000001011… |
… | …000001001011010010111 |
3 | 21002020101121021112201002 |
4 | 131013001120021122113 |
5 | 230233311424002320 |
6 | 4130550054453515 |
7 | 264344610341030 |
oct | 35070130113227 |
9 | 7066347245632 |
10 | 2000404125335 |
11 | 701403a84170 |
12 | 28383736429b |
13 | 1168391bb5a5 |
14 | 6cb6a409a87 |
15 | 3707d708675 |
hex | 1d1c1609697 |
2000404125335 has 16 divisors (see below), whose sum is σ = 2992812406272. Its totient is φ = 1247005168800.
The previous prime is 2000404125329. The next prime is 2000404125389. The reversal of 2000404125335 is 5335214040002.
It is a happy number.
It is not a de Polignac number, because 2000404125335 - 230 = 1999330383511 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2000404125298 and 2000404125307.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2597927051 + ... + 2597927820.
It is an arithmetic number, because the mean of its divisors is an integer number (187050775392).
Almost surely, 22000404125335 is an apocalyptic number.
2000404125335 is a deficient number, since it is larger than the sum of its proper divisors (992408280937).
2000404125335 is a wasteful number, since it uses less digits than its factorization.
2000404125335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5195854894.
The product of its (nonzero) digits is 14400, while the sum is 29.
Adding to 2000404125335 its reverse (5335214040002), we get a palindrome (7335618165337).
The spelling of 2000404125335 in words is "two trillion, four hundred four million, one hundred twenty-five thousand, three hundred thirty-five".
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