Base | Representation |
---|---|
bin | 111011100111100… |
… | …0011001101011101 |
3 | 12011102011120120122 |
4 | 1313033003031131 |
5 | 13044102342023 |
6 | 530300124325 |
7 | 100400260064 |
oct | 16717031535 |
9 | 5142146518 |
10 | 2000434013 |
11 | 937213756 |
12 | 479b366a5 |
13 | 25b599a86 |
14 | 14d96d1db |
15 | ba94b2c8 |
hex | 773c335d |
2000434013 has 6 divisors (see below), whose sum is σ = 2125028826. Its totient is φ = 1882761152.
The previous prime is 2000434001. The next prime is 2000434027. The reversal of 2000434013 is 3104340002.
It can be written as a sum of positive squares in 3 ways, for example, as 1145280964 + 855153049 = 33842^2 + 29243^2 .
It is not a de Polignac number, because 2000434013 - 212 = 2000429917 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2000433982 and 2000434000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2000434213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3460670 + ... + 3461247.
It is an arithmetic number, because the mean of its divisors is an integer number (354171471).
Almost surely, 22000434013 is an apocalyptic number.
It is an amenable number.
2000434013 is a deficient number, since it is larger than the sum of its proper divisors (124594813).
2000434013 is an equidigital number, since it uses as much as digits as its factorization.
2000434013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6921951 (or 6921934 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 17.
The square root of 2000434013 is about 44726.2116996287. The cubic root of 2000434013 is about 1260.0121803223.
Adding to 2000434013 its reverse (3104340002), we get a palindrome (5104774015).
The spelling of 2000434013 in words is "two billion, four hundred thirty-four thousand, thirteen".
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