Base | Representation |
---|---|
bin | 1001000110010111111011… |
… | …00001111111100000100111 |
3 | 2121211221212000122210012222 |
4 | 10203023331201333200213 |
5 | 10110321403032230203 |
6 | 110320321503502555 |
7 | 4133455454624135 |
oct | 443137541774047 |
9 | 77757760583188 |
10 | 20010211211303 |
11 | 6415312622245 |
12 | 22b21432b7a5b |
13 | b21c549824c1 |
14 | 4d26dc480755 |
15 | 24a7a1565038 |
hex | 1232fd87f827 |
20010211211303 has 4 divisors (see below), whose sum is σ = 20498265143328. Its totient is φ = 19522157279280.
The previous prime is 20010211211297. The next prime is 20010211211317. The reversal of 20010211211303 is 30311211201002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20010211211303 - 26 = 20010211211239 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20010211213303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 244026965951 + ... + 244026966032.
It is an arithmetic number, because the mean of its divisors is an integer number (5124566285832).
Almost surely, 220010211211303 is an apocalyptic number.
20010211211303 is a deficient number, since it is larger than the sum of its proper divisors (488053932025).
20010211211303 is an equidigital number, since it uses as much as digits as its factorization.
20010211211303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 488053932024.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 20010211211303 its reverse (30311211201002), we get a palindrome (50321422412305).
The spelling of 20010211211303 in words is "twenty trillion, ten billion, two hundred eleven million, two hundred eleven thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.189 sec. • engine limits •