Base | Representation |
---|---|
bin | 10010101000110000… |
… | …011010001001101111 |
3 | 1220122121110210210122 |
4 | 102220300122021233 |
5 | 311440322202003 |
6 | 13105403555155 |
7 | 1305615545156 |
oct | 225060321157 |
9 | 56577423718 |
10 | 20011131503 |
11 | 8539842310 |
12 | 3a6582babb |
13 | 1b6baa451c |
14 | d7b98259d |
15 | 7c1c19238 |
hex | 4a8c1a26f |
20011131503 has 4 divisors (see below), whose sum is σ = 21830325288. Its totient is φ = 18191937720.
The previous prime is 20011131473. The next prime is 20011131509. The reversal of 20011131503 is 30513111002.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 20011131503 - 214 = 20011115119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20011131509) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 909596876 + ... + 909596897.
It is an arithmetic number, because the mean of its divisors is an integer number (5457581322).
Almost surely, 220011131503 is an apocalyptic number.
20011131503 is a deficient number, since it is larger than the sum of its proper divisors (1819193785).
20011131503 is a wasteful number, since it uses less digits than its factorization.
20011131503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1819193784.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 20011131503 its reverse (30513111002), we get a palindrome (50524242505).
The spelling of 20011131503 in words is "twenty billion, eleven million, one hundred thirty-one thousand, five hundred three".
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