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200120131311 = 366706710437
BaseRepresentation
bin1011101001100000010…
…1101101111011101111
3201010112201022222200020
42322120011231323233
511234321223200221
6231533420533223
720313110023032
oct2723005557357
9633481288606
10200120131311
1177963662681
123294b9b1213
1315b43190aa9
149986033019
155313ca3ac6
hex2e9816deef

200120131311 has 4 divisors (see below), whose sum is σ = 266826841752. Its totient is φ = 133413420872.

The previous prime is 200120131303. The next prime is 200120131313. The reversal of 200120131311 is 113131021002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200120131311 - 23 = 200120131303 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200120131313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33353355216 + ... + 33353355221.

It is an arithmetic number, because the mean of its divisors is an integer number (66706710438).

Almost surely, 2200120131311 is an apocalyptic number.

200120131311 is a deficient number, since it is larger than the sum of its proper divisors (66706710441).

200120131311 is an equidigital number, since it uses as much as digits as its factorization.

200120131311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66706710440.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 200120131311 its reverse (113131021002), we get a palindrome (313251152313).

The spelling of 200120131311 in words is "two hundred billion, one hundred twenty million, one hundred thirty-one thousand, three hundred eleven".

Divisors: 1 3 66706710437 200120131311