Base | Representation |
---|---|
bin | 11101000111110010000… |
… | …000111000011010111011 |
3 | 21002022111110200212020202 |
4 | 131013302000320122323 |
5 | 230241444322010021 |
6 | 4131203044112415 |
7 | 264404046161063 |
oct | 35076200703273 |
9 | 7068443625222 |
10 | 2001220110011 |
11 | 701792642571 |
12 | 283a2469570b |
13 | 11693927a065 |
14 | 6cc069363a3 |
15 | 370ca18ba0b |
hex | 1d1f20386bb |
2001220110011 has 2 divisors, whose sum is σ = 2001220110012. Its totient is φ = 2001220110010.
The previous prime is 2001220109981. The next prime is 2001220110041. The reversal of 2001220110011 is 1100110221002.
It is a balanced prime because it is at equal distance from previous prime (2001220109981) and next prime (2001220110041).
It is a cyclic number.
It is not a de Polignac number, because 2001220110011 - 214 = 2001220093627 is a prime.
It is a super-4 number, since 4×20012201100114 (a number of 50 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2001220109974 and 2001220110001.
It is not a weakly prime, because it can be changed into another prime (2001220110041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1000610055005 + 1000610055006.
It is an arithmetic number, because the mean of its divisors is an integer number (1000610055006).
Almost surely, 22001220110011 is an apocalyptic number.
2001220110011 is a deficient number, since it is larger than the sum of its proper divisors (1).
2001220110011 is an equidigital number, since it uses as much as digits as its factorization.
2001220110011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 2001220110011 its reverse (1100110221002), we get a palindrome (3101330331013).
The spelling of 2001220110011 in words is "two trillion, one billion, two hundred twenty million, one hundred ten thousand, eleven".
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