Base | Representation |
---|---|
bin | 1001000110011111000100… |
… | …11110111110100101100011 |
3 | 2121212022202201112120101200 |
4 | 10203033202132332211203 |
5 | 10110402234403403210 |
6 | 110322155001532243 |
7 | 4133652606335310 |
oct | 443174236764543 |
9 | 77768681476350 |
10 | 20014052403555 |
11 | 6416a038a88a1 |
12 | 22b2a357a4083 |
13 | b22417710022 |
14 | 4d2984695d07 |
15 | 24a9288bb0c0 |
hex | 1233e27be963 |
20014052403555 has 24 divisors (see below), whose sum is σ = 39646884761952. Its totient is φ = 9149281098624.
The previous prime is 20014052403529. The next prime is 20014052403563. The reversal of 20014052403555 is 55530425041002.
20014052403555 is a `hidden beast` number, since 2 + 0 + 0 + 1 + 405 + 240 + 3 + 5 + 5 + 5 = 666.
It is not a de Polignac number, because 20014052403555 - 214 = 20014052387171 is a prime.
It is a super-2 number, since 2×200140524035552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31768336834 + ... + 31768337463.
It is an arithmetic number, because the mean of its divisors is an integer number (1651953531748).
Almost surely, 220014052403555 is an apocalyptic number.
20014052403555 is a deficient number, since it is larger than the sum of its proper divisors (19632832358397).
20014052403555 is a wasteful number, since it uses less digits than its factorization.
20014052403555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63536674315 (or 63536674312 counting only the distinct ones).
The product of its (nonzero) digits is 120000, while the sum is 36.
Adding to 20014052403555 its reverse (55530425041002), we get a palindrome (75544477444557).
The spelling of 20014052403555 in words is "twenty trillion, fourteen billion, fifty-two million, four hundred three thousand, five hundred fifty-five".
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