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200203201301 = 521384267181
BaseRepresentation
bin1011101001110100001…
…0100110101100010101
3201010202111122101021112
42322131002212230111
511240004004420201
6231545545224405
720315136063425
oct2723502465425
9633674571245
10200203201301
11779a6540364
1232973792105
1315b5745762c
149993098485
15531b2120bb
hex2e9d0a6b15

200203201301 has 4 divisors (see below), whose sum is σ = 200587469004. Its totient is φ = 199818933600.

The previous prime is 200203201277. The next prime is 200203201327. The reversal of 200203201301 is 103102302002.

It is a happy number.

200203201301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 134564248900 + 65638952401 = 366830^2 + 256201^2 .

It is a cyclic number.

It is not a de Polignac number, because 200203201301 - 210 = 200203200277 is a prime.

It is a super-2 number, since 2×2002032013012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200203201201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 192133070 + ... + 192134111.

It is an arithmetic number, because the mean of its divisors is an integer number (50146867251).

Almost surely, 2200203201301 is an apocalyptic number.

It is an amenable number.

200203201301 is a deficient number, since it is larger than the sum of its proper divisors (384267703).

200203201301 is an equidigital number, since it uses as much as digits as its factorization.

200203201301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 384267702.

The product of its (nonzero) digits is 72, while the sum is 14.

Adding to 200203201301 its reverse (103102302002), we get a palindrome (303305503303).

The spelling of 200203201301 in words is "two hundred billion, two hundred three million, two hundred one thousand, three hundred one".

Divisors: 1 521 384267181 200203201301