Base | Representation |
---|---|
bin | 101101100001010110100111… |
… | …000100000111101001001000 |
3 | 222020212022210220002022121101 |
4 | 231201112213010013221020 |
5 | 202220121011020142100 |
6 | 1545444300000551144 |
7 | 60112161365051053 |
oct | 5541264704075110 |
9 | 866768726068541 |
10 | 200204113443400 |
11 | 588780a6801450 |
12 | 1a554a946224b4 |
13 | 879322286c221 |
14 | 3761d06149a9a |
15 | 1822b7d6e686a |
hex | b615a7107a48 |
200204113443400 has 48 divisors (see below), whose sum is σ = 507790433193840. Its totient is φ = 72801495796800.
The previous prime is 200204113443361. The next prime is 200204113443401. The reversal of 200204113443400 is 4344311402002.
It is not an unprimeable number, because it can be changed into a prime (200204113443401) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 45500932674 + ... + 45500937073.
It is an arithmetic number, because the mean of its divisors is an integer number (10578967358205).
Almost surely, 2200204113443400 is an apocalyptic number.
200204113443400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
200204113443400 is an abundant number, since it is smaller than the sum of its proper divisors (307586319750440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
200204113443400 is a wasteful number, since it uses less digits than its factorization.
200204113443400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91001869774 (or 91001869765 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 200204113443400 its reverse (4344311402002), we get a palindrome (204548424845402).
The spelling of 200204113443400 in words is "two hundred trillion, two hundred four billion, one hundred thirteen million, four hundred forty-three thousand, four hundred".
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