Base | Representation |
---|---|
bin | 1001000110101100000001… |
… | …01101111101110110001111 |
3 | 2121212222201001121201211102 |
4 | 10203112000231331312033 |
5 | 10111011003014200421 |
6 | 110325304342013315 |
7 | 4134320044644305 |
oct | 443260055756617 |
9 | 77788631551742 |
10 | 20021002100111 |
11 | 641994a814771 |
12 | 22b425511723b |
13 | b22c844826cc |
14 | 4d304367a275 |
15 | 24abd3a9a60b |
hex | 123580b7dd8f |
20021002100111 has 2 divisors, whose sum is σ = 20021002100112. Its totient is φ = 20021002100110.
The previous prime is 20021002100087. The next prime is 20021002100167. The reversal of 20021002100111 is 11100120012002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20021002100111 - 214 = 20021002083727 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20021002100092 and 20021002100101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021002100611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010501050055 + 10010501050056.
It is an arithmetic number, because the mean of its divisors is an integer number (10010501050056).
Almost surely, 220021002100111 is an apocalyptic number.
20021002100111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021002100111 is an equidigital number, since it uses as much as digits as its factorization.
20021002100111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 20021002100111 its reverse (11100120012002), we get a palindrome (31121122112113).
The spelling of 20021002100111 in words is "twenty trillion, twenty-one billion, two million, one hundred thousand, one hundred eleven".
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