Base | Representation |
---|---|
bin | 101101100001011101000001… |
… | …100110011100011110101111 |
3 | 222020212222120220102112111122 |
4 | 231201131001212130132233 |
5 | 202220224112240201312 |
6 | 1545451355243211155 |
7 | 60112524151136126 |
oct | 5541350146343657 |
9 | 866788526375448 |
10 | 200211001100207 |
11 | 588800106a39a9 |
12 | 1a556297216abb |
13 | 8793a7c7cc3b6 |
14 | 376239abc0abd |
15 | 1822e3321db72 |
hex | b6174199c7af |
200211001100207 has 2 divisors, whose sum is σ = 200211001100208. Its totient is φ = 200211001100206.
The previous prime is 200211001100177. The next prime is 200211001100237. The reversal of 200211001100207 is 702001100112002.
It is a balanced prime because it is at equal distance from previous prime (200211001100177) and next prime (200211001100237).
It is a cyclic number.
It is not a de Polignac number, because 200211001100207 - 212 = 200211001096111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200211001100237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105500550103 + 100105500550104.
It is an arithmetic number, because the mean of its divisors is an integer number (100105500550104).
Almost surely, 2200211001100207 is an apocalyptic number.
200211001100207 is a deficient number, since it is larger than the sum of its proper divisors (1).
200211001100207 is an equidigital number, since it uses as much as digits as its factorization.
200211001100207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 17.
Adding to 200211001100207 its reverse (702001100112002), we get a palindrome (902212101212209).
The spelling of 200211001100207 in words is "two hundred trillion, two hundred eleven billion, one million, one hundred thousand, two hundred seven".
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