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2002110202013 is a prime number
BaseRepresentation
bin11101001000100111000…
…100010100000010011101
321002101210111120012221012
4131020213010110002131
5230300310202431023
64131431241545005
7264435104632355
oct35104704240235
97071714505835
102002110202013
117020aa017899
122840327a5165
13116a4b7b4a0c
146cc8cc33b65
153712d3ac978
hex1d22711409d

2002110202013 has 2 divisors, whose sum is σ = 2002110202014. Its totient is φ = 2002110202012.

The previous prime is 2002110202009. The next prime is 2002110202049. The reversal of 2002110202013 is 3102020112002.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1325302883524 + 676807318489 = 1151218^2 + 822683^2 .

It is a cyclic number.

It is not a de Polignac number, because 2002110202013 - 22 = 2002110202009 is a prime.

It is a super-2 number, since 2×20021102020132 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2002110202003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001055101006 + 1001055101007.

It is an arithmetic number, because the mean of its divisors is an integer number (1001055101007).

Almost surely, 22002110202013 is an apocalyptic number.

It is an amenable number.

2002110202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2002110202013 is an equidigital number, since it uses as much as digits as its factorization.

2002110202013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 2002110202013 its reverse (3102020112002), we get a palindrome (5104130314015).

The spelling of 2002110202013 in words is "two trillion, two billion, one hundred ten million, two hundred two thousand, thirteen".