Base | Representation |
---|---|
bin | 11101001000100111001… |
… | …011111011110101000100 |
3 | 21002101210122022201122212 |
4 | 131020213023323311010 |
5 | 230300311210400004 |
6 | 4131431352442552 |
7 | 264435130623410 |
oct | 35104713736504 |
9 | 7071718281585 |
10 | 2002112200004 |
11 | 702100161a24 |
12 | 2840333a9458 |
13 | 116a4c034267 |
14 | 6cc8d1d3d40 |
15 | 3712d65496e |
hex | 1d2272fbd44 |
2002112200004 has 48 divisors (see below), whose sum is σ = 4254365445120. Its totient is φ = 805290556320.
The previous prime is 2002112200003. The next prime is 2002112200009. The reversal of 2002112200004 is 4000022112002.
It is a super-2 number, since 2×20021122000042 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (14).
It is not an unprimeable number, because it can be changed into a prime (2002112200003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17528912 + ... + 17642759.
It is an arithmetic number, because the mean of its divisors is an integer number (88632613440).
Almost surely, 22002112200004 is an apocalyptic number.
It is an amenable number.
2002112200004 is an abundant number, since it is smaller than the sum of its proper divisors (2252253245116).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2002112200004 is a wasteful number, since it uses less digits than its factorization.
2002112200004 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35171808 (or 35171806 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 2002112200004 its reverse (4000022112002), we get a palindrome (6002134312006).
The spelling of 2002112200004 in words is "two trillion, two billion, one hundred twelve million, two hundred thousand, four".
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