Base | Representation |
---|---|
bin | 1001000110101100001111… |
… | …10111110001010001010111 |
3 | 2121220000000102102220012112 |
4 | 10203112013313301101113 |
5 | 10111011224230014201 |
6 | 110325324310141235 |
7 | 4134323033011052 |
oct | 443260767612127 |
9 | 77800012386175 |
10 | 20021122110551 |
11 | 6419a01533351 |
12 | 22b428935181b |
13 | b22ca32b12c3 |
14 | 4d3055599a99 |
15 | 24abde3a40bb |
hex | 123587df1457 |
20021122110551 has 2 divisors, whose sum is σ = 20021122110552. Its totient is φ = 20021122110550.
The previous prime is 20021122110527. The next prime is 20021122110553. The reversal of 20021122110551 is 15501122112002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20021122110551 - 214 = 20021122094167 is a prime.
Together with 20021122110553, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20021122110553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10010561055275 + 10010561055276.
It is an arithmetic number, because the mean of its divisors is an integer number (10010561055276).
Almost surely, 220021122110551 is an apocalyptic number.
20021122110551 is a deficient number, since it is larger than the sum of its proper divisors (1).
20021122110551 is an equidigital number, since it uses as much as digits as its factorization.
20021122110551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 400, while the sum is 23.
Adding to 20021122110551 its reverse (15501122112002), we get a palindrome (35522244222553).
The spelling of 20021122110551 in words is "twenty trillion, twenty-one billion, one hundred twenty-two million, one hundred ten thousand, five hundred fifty-one".
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