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2002122013301 = 2387048783187
BaseRepresentation
bin11101001000100111110…
…001010111101001110101
321002101211022210021222022
4131020213301113221311
5230300321213411201
64131432343042525
7264435310214534
oct35104761275165
97071738707868
102002122013301
11702105754893
12284036740445
13116a5108bb47
146cc9062a31b
153712e44241b
hex1d227c57a75

2002122013301 has 4 divisors (see below), whose sum is σ = 2089170796512. Its totient is φ = 1915073230092.

The previous prime is 2002122013267. The next prime is 2002122013327. The reversal of 2002122013301 is 1033102212002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002122013301 - 26 = 2002122013237 is a prime.

It is a super-2 number, since 2×20021220133012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2002122013301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2002122013361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43524391571 + ... + 43524391616.

It is an arithmetic number, because the mean of its divisors is an integer number (522292699128).

Almost surely, 22002122013301 is an apocalyptic number.

It is an amenable number.

2002122013301 is a deficient number, since it is larger than the sum of its proper divisors (87048783211).

2002122013301 is an equidigital number, since it uses as much as digits as its factorization.

2002122013301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87048783210.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2002122013301 its reverse (1033102212002), we get a palindrome (3035224225303).

The spelling of 2002122013301 in words is "two trillion, two billion, one hundred twenty-two million, thirteen thousand, three hundred one".

Divisors: 1 23 87048783187 2002122013301