Base | Representation |
---|---|
bin | 1001000110101100100110… |
… | …00100100011001100010101 |
3 | 2121220000111112000011222022 |
4 | 10203112103010203030111 |
5 | 10111012120330311013 |
6 | 110325355101342525 |
7 | 4134330504100205 |
oct | 443262304431425 |
9 | 77800445004868 |
10 | 20021310010133 |
11 | 6419a98601063 |
12 | 22b4320267a45 |
13 | b230031bc9a3 |
14 | 4d307250c405 |
15 | 24ac00b1d008 |
hex | 123593123315 |
20021310010133 has 4 divisors (see below), whose sum is σ = 20891801749728. Its totient is φ = 19150818270540.
The previous prime is 20021310010111. The next prime is 20021310010181. The reversal of 20021310010133 is 33101001312002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20021310010133 - 210 = 20021310009109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20021310010103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435245869763 + ... + 435245869808.
It is an arithmetic number, because the mean of its divisors is an integer number (5222950437432).
Almost surely, 220021310010133 is an apocalyptic number.
20021310010133 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
20021310010133 is a deficient number, since it is larger than the sum of its proper divisors (870491739595).
20021310010133 is an equidigital number, since it uses as much as digits as its factorization.
20021310010133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 870491739594.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 20021310010133 its reverse (33101001312002), we get a palindrome (53122311322135).
The spelling of 20021310010133 in words is "twenty trillion, twenty-one billion, three hundred ten million, ten thousand, one hundred thirty-three".
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