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200220011111 = 508139405631
BaseRepresentation
bin1011101001111000001…
…0101110101001100111
3201010210200021102000002
42322132002232221213
511240022310323421
6231551345411515
720315432004551
oct2723602565147
9633720242002
10200220011111
1177a04a8186a
1232979339b9b
1315b5aa91973
1499953d24d1
15531c932b0b
hex2e9e0aea67

200220011111 has 4 divisors (see below), whose sum is σ = 200259421824. Its totient is φ = 200180600400.

The previous prime is 200220011093. The next prime is 200220011113. The reversal of 200220011111 is 111110022002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200220011111 - 226 = 200152902247 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200220011092 and 200220011101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200220011113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19697735 + ... + 19707896.

It is an arithmetic number, because the mean of its divisors is an integer number (50064855456).

Almost surely, 2200220011111 is an apocalyptic number.

200220011111 is a deficient number, since it is larger than the sum of its proper divisors (39410713).

200220011111 is an equidigital number, since it uses as much as digits as its factorization.

200220011111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39410712.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 200220011111 its reverse (111110022002), we get a palindrome (311330033113).

The spelling of 200220011111 in words is "two hundred billion, two hundred twenty million, eleven thousand, one hundred eleven".

Divisors: 1 5081 39405631 200220011111