Base | Representation |
---|---|
bin | 1001000110101111110011… |
… | …00111110100000111100111 |
3 | 2121220011221102110200021011 |
4 | 10203113321213310013213 |
5 | 10111024131303434120 |
6 | 110330241522203051 |
7 | 4134421235216524 |
oct | 443277147640747 |
9 | 77804842420234 |
10 | 20023030530535 |
11 | 641a7a080a54a |
12 | 22b47204b3487 |
13 | b232187a24b6 |
14 | 4d3196c1614b |
15 | 24aca1bc6c5a |
hex | 1235f99f41e7 |
20023030530535 has 32 divisors (see below), whose sum is σ = 24604684473600. Its totient is φ = 15638682009600.
The previous prime is 20023030530521. The next prime is 20023030530539. The reversal of 20023030530535 is 53503503032002.
It is a de Polignac number, because none of the positive numbers 2k-20023030530535 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20023030530497 and 20023030530506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (20023030530539) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 30352927 + ... + 31005583.
It is an arithmetic number, because the mean of its divisors is an integer number (768896389800).
Almost surely, 220023030530535 is an apocalyptic number.
20023030530535 is a deficient number, since it is larger than the sum of its proper divisors (4581653943065).
20023030530535 is a wasteful number, since it uses less digits than its factorization.
20023030530535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 653611.
The product of its (nonzero) digits is 40500, while the sum is 31.
Adding to 20023030530535 its reverse (53503503032002), we get a palindrome (73526533562537).
The spelling of 20023030530535 in words is "twenty trillion, twenty-three billion, thirty million, five hundred thirty thousand, five hundred thirty-five".
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