Base | Representation |
---|---|
bin | 10010101001011110… |
… | …001001010101001111 |
3 | 1220200110000221121122 |
4 | 102221132021111033 |
5 | 312001404334411 |
6 | 13110512551155 |
7 | 1306122502511 |
oct | 225136112517 |
9 | 56613027548 |
10 | 20023121231 |
11 | 8545591383 |
12 | 3a698524bb |
13 | 1b71411939 |
14 | d7d3c3bb1 |
15 | 7c2cd69db |
hex | 4a978954f |
20023121231 has 2 divisors, whose sum is σ = 20023121232. Its totient is φ = 20023121230.
The previous prime is 20023121227. The next prime is 20023121233. The reversal of 20023121231 is 13212132002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20023121231 - 22 = 20023121227 is a prime.
It is a super-3 number, since 3×200231212313 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
Together with 20023121233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20023121233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10011560615 + 10011560616.
It is an arithmetic number, because the mean of its divisors is an integer number (10011560616).
Almost surely, 220023121231 is an apocalyptic number.
20023121231 is a deficient number, since it is larger than the sum of its proper divisors (1).
20023121231 is an equidigital number, since it uses as much as digits as its factorization.
20023121231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 20023121231 its reverse (13212132002), we get a palindrome (33235253233).
The spelling of 20023121231 in words is "twenty billion, twenty-three million, one hundred twenty-one thousand, two hundred thirty-one".
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