Base | Representation |
---|---|
bin | 1011101001111100111… |
… | …1011110100000000011 |
3 | 201010212002010120000000 |
4 | 2322133033132200003 |
5 | 11240042433130201 |
6 | 231553344531043 |
7 | 20316065010423 |
oct | 2723717364003 |
9 | 633762116000 |
10 | 200240130051 |
11 | 77a15373495 |
12 | 32984020a83 |
13 | 15b61cb7270 |
14 | 9997d4c483 |
15 | 531e5a8d86 |
hex | 2e9f3de803 |
200240130051 has 128 divisors (see below), whose sum is σ = 333022126080. Its totient is φ = 119597057280.
The previous prime is 200240129993. The next prime is 200240130067. The reversal of 200240130051 is 150031042002.
It is not a de Polignac number, because 200240130051 - 27 = 200240129923 is a prime.
It is a super-2 number, since 2×2002401300512 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (200240130071) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 329884590 + ... + 329885196.
It is an arithmetic number, because the mean of its divisors is an integer number (2601735360).
Almost surely, 2200240130051 is an apocalyptic number.
200240130051 is a deficient number, since it is larger than the sum of its proper divisors (132781996029).
200240130051 is an equidigital number, since it uses as much as digits as its factorization.
200240130051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 965 (or 947 counting only the distinct ones).
The product of its (nonzero) digits is 240, while the sum is 18.
Adding to 200240130051 its reverse (150031042002), we get a palindrome (350271172053).
The spelling of 200240130051 in words is "two hundred billion, two hundred forty million, one hundred thirty thousand, fifty-one".
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