Base | Representation |
---|---|
bin | 10010101001111000… |
… | …110110100001111111 |
3 | 1220200221012122000111 |
4 | 102221320312201333 |
5 | 312010202401421 |
6 | 13111323010451 |
7 | 1306236141316 |
oct | 225170664177 |
9 | 56627178014 |
10 | 20030122111 |
11 | 854953322a |
12 | 3a70069a27 |
13 | 1b729c337c |
14 | d802c727d |
15 | 7c371aee1 |
hex | 4a9e3687f |
20030122111 has 2 divisors, whose sum is σ = 20030122112. Its totient is φ = 20030122110.
The previous prime is 20030122093. The next prime is 20030122129. The reversal of 20030122111 is 11122103002.
It is a balanced prime because it is at equal distance from previous prime (20030122093) and next prime (20030122129).
It is a cyclic number.
It is not a de Polignac number, because 20030122111 - 211 = 20030120063 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20030122091 and 20030122100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20030122811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10015061055 + 10015061056.
It is an arithmetic number, because the mean of its divisors is an integer number (10015061056).
Almost surely, 220030122111 is an apocalyptic number.
20030122111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20030122111 is an equidigital number, since it uses as much as digits as its factorization.
20030122111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20030122111 its reverse (11122103002), we get a palindrome (31152225113).
The spelling of 20030122111 in words is "twenty billion, thirty million, one hundred twenty-two thousand, one hundred eleven".
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