Base | Representation |
---|---|
bin | 1001000110111101100111… |
… | …11110100011010100101101 |
3 | 2121220220002122022102121210 |
4 | 10203132303332203110231 |
5 | 10111134331204124100 |
6 | 110333510154345033 |
7 | 4135103162643552 |
oct | 443366376432455 |
9 | 77826078272553 |
10 | 20030452020525 |
11 | 6422959a77851 |
12 | 22b6051a2b179 |
13 | b23b2c2023ab |
14 | 4d369c72ca29 |
15 | 24b0884ebc50 |
hex | 1237b3fa352d |
20030452020525 has 12 divisors (see below), whose sum is σ = 33117014007392. Its totient is φ = 10682907744240.
The previous prime is 20030452020493. The next prime is 20030452020539. The reversal of 20030452020525 is 52502025403002.
It is not a de Polignac number, because 20030452020525 - 25 = 20030452020493 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 20030452020492 and 20030452020501.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 133536346729 + ... + 133536346878.
Almost surely, 220030452020525 is an apocalyptic number.
20030452020525 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
20030452020525 is a deficient number, since it is larger than the sum of its proper divisors (13086561986867).
20030452020525 is a wasteful number, since it uses less digits than its factorization.
20030452020525 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 267072693620 (or 267072693615 counting only the distinct ones).
The product of its (nonzero) digits is 24000, while the sum is 30.
Adding to 20030452020525 its reverse (52502025403002), we get a palindrome (72532477423527).
The spelling of 20030452020525 in words is "twenty trillion, thirty billion, four hundred fifty-two million, twenty thousand, five hundred twenty-five".
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