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2003113103 = 10119832803
BaseRepresentation
bin111011101100101…
…0001010010001111
312011121012200121012
41313121101102033
513100244104403
6530433355435
7100432115615
oct16731212217
95147180535
102003113103
11938783582
1247aa08b7b
1325bcc7334
141500696b5
15bacc9ed8
hex7765148f

2003113103 has 4 divisors (see below), whose sum is σ = 2022946008. Its totient is φ = 1983280200.

The previous prime is 2003113061. The next prime is 2003113117. The reversal of 2003113103 is 3013113002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003113103 - 26 = 2003113039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003113183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9916301 + ... + 9916502.

It is an arithmetic number, because the mean of its divisors is an integer number (505736502).

Almost surely, 22003113103 is an apocalyptic number.

2003113103 is a deficient number, since it is larger than the sum of its proper divisors (19832905).

2003113103 is a wasteful number, since it uses less digits than its factorization.

2003113103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19832904.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 2003113103 is about 44756.1515660138. The cubic root of 2003113103 is about 1260.5744216765.

Adding to 2003113103 its reverse (3013113002), we get a palindrome (5016226105).

The spelling of 2003113103 in words is "two billion, three million, one hundred thirteen thousand, one hundred three".

Divisors: 1 101 19832803 2003113103