2003120111 has 4 divisors (see below), whose sum is σ = 2003383800. Its totient is φ = 2002856424.

The previous prime is 2003120069. The next prime is 2003120113. The reversal of 2003120111 is 1110213002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2003120111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003120092 and 2003120101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2003120113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120101 + ... + 135758.

It is an arithmetic number, because the mean of its divisors is an integer number (500845950).

Almost surely, 2^2003120111 is an apocalyptic number.

2003120111 is a deficient number, since it is larger than the sum of its proper divisors (263689).

2003120111 is an equidigital number, since it uses as much as digits as its factorization.

2003120111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 263688.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 2003120111 is about 44756.2298568590. The cubic root of 2003120111 is about 1260.5758917374.

Adding to 2003120111 its reverse (1110213002), we get a palindrome (3113333113).

The spelling of 2003120111 in words is "two billion, three million, one hundred twenty thousand, one hundred eleven".