Base | Representation |
---|---|
bin | 1111011100000000100… |
… | …11000010100001010011 |
3 | 1212201010211010021010200 |
4 | 13232000103002201103 |
5 | 32142311430431430 |
6 | 1043402221430243 |
7 | 53215430644110 |
oct | 7560023024123 |
9 | 1781124107120 |
10 | 530433452115 |
11 | 194a56945516 |
12 | 8697510b383 |
13 | 3b0342677c8 |
14 | 1b95d05d907 |
15 | dbe782c460 |
hex | 7b804c2853 |
530433452115 has 96 divisors (see below), whose sum is σ = 1098823864320. Its totient is φ = 231438670848.
The previous prime is 530433452083. The next prime is 530433452117. The reversal of 530433452115 is 511254334035.
530433452115 is a `hidden beast` number, since 5 + 3 + 0 + 433 + 4 + 5 + 211 + 5 = 666.
It is not a de Polignac number, because 530433452115 - 25 = 530433452083 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 530433452115.
It is not an unprimeable number, because it can be changed into a prime (530433452117) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3275371 + ... + 3433499.
It is an arithmetic number, because the mean of its divisors is an integer number (11446081920).
Almost surely, 2530433452115 is an apocalyptic number.
530433452115 is an abundant number, since it is smaller than the sum of its proper divisors (568390412205).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530433452115 is a wasteful number, since it uses less digits than its factorization.
530433452115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158633 (or 158630 counting only the distinct ones).
The product of its (nonzero) digits is 108000, while the sum is 36.
The spelling of 530433452115 in words is "five hundred thirty billion, four hundred thirty-three million, four hundred fifty-two thousand, one hundred fifteen".
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