Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100100011110010111101 |
3 | 21002111101221201211210112 |
4 | 131021203110203302331 |
5 | 230304343000000241 |
6 | 4132115432515405 |
7 | 264502131235661 |
oct | 35114324436275 |
9 | 7074357654715 |
10 | 2003121093821 |
11 | 7025786aa871 |
12 | 28427524bb65 |
13 | 116b80066653 |
14 | 6cd471b88a1 |
15 | 3718bee11eb |
hex | 1d263523cbd |
2003121093821 has 2 divisors, whose sum is σ = 2003121093822. Its totient is φ = 2003121093820.
The previous prime is 2003121093793. The next prime is 2003121093823. The reversal of 2003121093821 is 1283901213002.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1940975589721 + 62145504100 = 1393189^2 + 249290^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2003121093821 is a prime.
Together with 2003121093823, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003121093823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001560546910 + 1001560546911.
It is an arithmetic number, because the mean of its divisors is an integer number (1001560546911).
Almost surely, 22003121093821 is an apocalyptic number.
It is an amenable number.
2003121093821 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003121093821 is an equidigital number, since it uses as much as digits as its factorization.
2003121093821 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 2003121093821 in words is "two trillion, three billion, one hundred twenty-one million, ninety-three thousand, eight hundred twenty-one".
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