Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100100011110010111111 |
3 | 21002111101221201211210121 |
4 | 131021203110203302333 |
5 | 230304343000000243 |
6 | 4132115432515411 |
7 | 264502131235663 |
oct | 35114324436277 |
9 | 7074357654717 |
10 | 2003121093823 |
11 | 7025786aa873 |
12 | 28427524bb67 |
13 | 116b80066655 |
14 | 6cd471b88a3 |
15 | 3718bee11ed |
hex | 1d263523cbf |
2003121093823 has 2 divisors, whose sum is σ = 2003121093824. Its totient is φ = 2003121093822.
The previous prime is 2003121093821. The next prime is 2003121093839. The reversal of 2003121093823 is 3283901213002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2003121093823 - 21 = 2003121093821 is a prime.
It is a super-3 number, since 3×20031210938233 (a number of 38 digits) contains 333 as substring.
Together with 2003121093821, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003121093821) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001560546911 + 1001560546912.
It is an arithmetic number, because the mean of its divisors is an integer number (1001560546912).
Almost surely, 22003121093823 is an apocalyptic number.
2003121093823 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003121093823 is an equidigital number, since it uses as much as digits as its factorization.
2003121093823 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
The spelling of 2003121093823 in words is "two trillion, three billion, one hundred twenty-one million, ninety-three thousand, eight hundred twenty-three".
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