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2003121102013 is a prime number
BaseRepresentation
bin11101001001100011010…
…100100101110010111101
321002111101221202021000221
4131021203110211302331
5230304343000231023
64132115433021341
7264502131301603
oct35114324456275
97074357667027
102003121102013
11702578705a39
12284275254851
13116b8006a2b5
146cd471bb873
153718bee385d
hex1d263525cbd

2003121102013 has 2 divisors, whose sum is σ = 2003121102014. Its totient is φ = 2003121102012.

The previous prime is 2003121102001. The next prime is 2003121102019. The reversal of 2003121102013 is 3102011213002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1124876602404 + 878244499609 = 1060602^2 + 937147^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003121102013 - 213 = 2003121093821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2003121102019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001560551006 + 1001560551007.

It is an arithmetic number, because the mean of its divisors is an integer number (1001560551007).

Almost surely, 22003121102013 is an apocalyptic number.

It is an amenable number.

2003121102013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003121102013 is an equidigital number, since it uses as much as digits as its factorization.

2003121102013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 2003121102013 its reverse (3102011213002), we get a palindrome (5105132315015).

The spelling of 2003121102013 in words is "two trillion, three billion, one hundred twenty-one million, one hundred two thousand, thirteen".