Base | Representation |
---|---|
bin | 11101001001100011010… |
… | …100100101110111011110 |
3 | 21002111101221202021102122 |
4 | 131021203110211313132 |
5 | 230304343000233202 |
6 | 4132115433022542 |
7 | 264502131302465 |
oct | 35114324456736 |
9 | 7074357667378 |
10 | 2003121102302 |
11 | 702578706181 |
12 | 284275254a52 |
13 | 116b8006a478 |
14 | 6cd471bb9dc |
15 | 3718bee39a2 |
hex | 1d263525dde |
2003121102302 has 4 divisors (see below), whose sum is σ = 3004681653456. Its totient is φ = 1001560551150.
The previous prime is 2003121102239. The next prime is 2003121102313. The reversal of 2003121102302 is 2032011213002.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500780275574 + ... + 500780275577.
It is an arithmetic number, because the mean of its divisors is an integer number (751170413364).
Almost surely, 22003121102302 is an apocalyptic number.
2003121102302 is a deficient number, since it is larger than the sum of its proper divisors (1001560551154).
2003121102302 is a wasteful number, since it uses less digits than its factorization.
2003121102302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1001560551153.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 2003121102302 its reverse (2032011213002), we get a palindrome (4035132315304).
The spelling of 2003121102302 in words is "two trillion, three billion, one hundred twenty-one million, one hundred two thousand, three hundred two".
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