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200314111103 = 1971016822899
BaseRepresentation
bin1011101010001110100…
…1101100010001111111
3201011001020100011220222
42322203221230101333
511240220403023403
6232004550331555
720320653564551
oct2724351542177
9634036304828
10200314111103
1177a53103557
12329a4959bbb
1315b7441ab32
1499a3ac94d1
155325d1e338
hex2ea3a6c47f

200314111103 has 4 divisors (see below), whose sum is σ = 201330934200. Its totient is φ = 199297288008.

The previous prime is 200314111097. The next prime is 200314111121. The reversal of 200314111103 is 301111413002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200314111103 - 228 = 200045675647 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200314111133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508411253 + ... + 508411646.

It is an arithmetic number, because the mean of its divisors is an integer number (50332733550).

Almost surely, 2200314111103 is an apocalyptic number.

200314111103 is a deficient number, since it is larger than the sum of its proper divisors (1016823097).

200314111103 is a wasteful number, since it uses less digits than its factorization.

200314111103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1016823096.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 200314111103 its reverse (301111413002), we get a palindrome (501425524105).

The spelling of 200314111103 in words is "two hundred billion, three hundred fourteen million, one hundred eleven thousand, one hundred three".

Divisors: 1 197 1016822899 200314111103