20032100000041 has 4 divisors (see below), whose sum is σ = 20903060869632. Its totient is φ = 19161139130452.

The previous prime is 20032099999997. The next prime is 20032100000051. The reversal of 20032100000041 is 14000000123002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20032100000041 - 2²⁹ = 20031563129129 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20032099999967 and 20032100000030.

It is not an unprimeable number, because it can be changed into a prime (20032100000051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435480434761 + ... + 435480434806.

It is an arithmetic number, because the mean of its divisors is an integer number (5225765217408).

Almost surely, 2^{20032100000041} is an apocalyptic number.

It is an amenable number.

20032100000041 is a deficient number, since it is larger than the sum of its proper divisors (870960869591).

20032100000041 is an equidigital number, since it uses as much as digits as its factorization.

20032100000041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 870960869590.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 20032100000041 its reverse (14000000123002), we get a palindrome (34032100123043).

The spelling of 20032100000041 in words is "twenty trillion, thirty-two billion, one hundred million, forty-one", and thus it is an aban number.