Base | Representation |
---|---|
bin | 1011101010010000001… |
… | …1111111001000001111 |
3 | 201011001201022101021012 |
4 | 2322210003333020033 |
5 | 11240224134112142 |
6 | 232005354155435 |
7 | 20321066303603 |
oct | 2724403771017 |
9 | 634051271235 |
10 | 200321004047 |
11 | 77a56a912aa |
12 | 329a7122b7b |
13 | 15b759923b8 |
14 | 99a49a1503 |
15 | 5326731882 |
hex | 2ea40ff20f |
200321004047 has 2 divisors, whose sum is σ = 200321004048. Its totient is φ = 200321004046.
The previous prime is 200321004017. The next prime is 200321004049. The reversal of 200321004047 is 740400123002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200321004047 - 218 = 200320741903 is a prime.
Together with 200321004049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200321004049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100160502023 + 100160502024.
It is an arithmetic number, because the mean of its divisors is an integer number (100160502024).
Almost surely, 2200321004047 is an apocalyptic number.
200321004047 is a deficient number, since it is larger than the sum of its proper divisors (1).
200321004047 is an equidigital number, since it uses as much as digits as its factorization.
200321004047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 23.
Adding to 200321004047 its reverse (740400123002), we get a palindrome (940721127049).
The spelling of 200321004047 in words is "two hundred billion, three hundred twenty-one million, four thousand, forty-seven".
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