Base | Representation |
---|---|
bin | 11101001001101001010… |
… | …010011110111111001101 |
3 | 21002111122221010102200012 |
4 | 131021221102132333031 |
5 | 230310044112310013 |
6 | 4132133410443005 |
7 | 264504455236010 |
oct | 35115122367715 |
9 | 7074587112605 |
10 | 2003221213133 |
11 | 70261a1729a8 |
12 | 2842a2893465 |
13 | 116b97a1c54a |
14 | 6cd565db377 |
15 | 37195bbb1a8 |
hex | 1d26949efcd |
2003221213133 has 64 divisors (see below), whose sum is σ = 2498140569600. Its totient is φ = 1567317040128.
The previous prime is 2003221213073. The next prime is 2003221213157. The reversal of 2003221213133 is 3313121223002.
It is not a de Polignac number, because 2003221213133 - 212 = 2003221209037 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2003221213099 and 2003221213108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2003221213333) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1027819043 + ... + 1027820991.
It is an arithmetic number, because the mean of its divisors is an integer number (39033446400).
Almost surely, 22003221213133 is an apocalyptic number.
It is an amenable number.
2003221213133 is a deficient number, since it is larger than the sum of its proper divisors (494919356467).
2003221213133 is a wasteful number, since it uses less digits than its factorization.
2003221213133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3594.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 2003221213133 its reverse (3313121223002), we get a palindrome (5316342436135).
The spelling of 2003221213133 in words is "two trillion, three billion, two hundred twenty-one million, two hundred thirteen thousand, one hundred thirty-three".
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