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20033131412051 is a prime number
BaseRepresentation
bin1001000111000010100111…
…01011100111101001010011
32121221011000101001121210222
410203201103223213221103
510111210323120141201
6110335032111143255
74135226446254632
oct443412353475123
977834011047728
1020033131412051
11642400446830a
1222b667b214b2b
13b24168351774
144d3874519519
1524b19386091b
hex123853ae7a53

20033131412051 has 2 divisors, whose sum is σ = 20033131412052. Its totient is φ = 20033131412050.

The previous prime is 20033131412017. The next prime is 20033131412053. The reversal of 20033131412051 is 15021413133002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 20033131412051 - 218 = 20033131149907 is a prime.

Together with 20033131412053, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 20033131412051.

It is not a weakly prime, because it can be changed into another prime (20033131412053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016565706025 + 10016565706026.

It is an arithmetic number, because the mean of its divisors is an integer number (10016565706026).

Almost surely, 220033131412051 is an apocalyptic number.

20033131412051 is a deficient number, since it is larger than the sum of its proper divisors (1).

20033131412051 is an equidigital number, since it uses as much as digits as its factorization.

20033131412051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 20033131412051 its reverse (15021413133002), we get a palindrome (35054544545053).

The spelling of 20033131412051 in words is "twenty trillion, thirty-three billion, one hundred thirty-one million, four hundred twelve thousand, fifty-one".