Base | Representation |
---|---|
bin | 10010101010000101… |
… | …000011010010111111 |
3 | 1220201011020002212112 |
4 | 102222011003102333 |
5 | 312012012221002 |
6 | 13111515324235 |
7 | 1306305261062 |
oct | 225205032277 |
9 | 56634202775 |
10 | 20033320127 |
11 | 8550317a17 |
12 | 3a7115067b |
13 | 1b73572ba2 |
14 | d808ba8d9 |
15 | 7c3b4d852 |
hex | 4aa1434bf |
20033320127 has 2 divisors, whose sum is σ = 20033320128. Its totient is φ = 20033320126.
The previous prime is 20033320079. The next prime is 20033320157. The reversal of 20033320127 is 72102333002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20033320127 - 214 = 20033303743 is a prime.
It is a super-2 number, since 2×200333201272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20033320157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10016660063 + 10016660064.
It is an arithmetic number, because the mean of its divisors is an integer number (10016660064).
Almost surely, 220033320127 is an apocalyptic number.
20033320127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20033320127 is an equidigital number, since it uses as much as digits as its factorization.
20033320127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 23.
Adding to 20033320127 its reverse (72102333002), we get a palindrome (92135653129).
The spelling of 20033320127 in words is "twenty billion, thirty-three million, three hundred twenty thousand, one hundred twenty-seven".
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