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200421327149 is a prime number
BaseRepresentation
bin1011101010101000001…
…0101100000100101101
3201011022201002022200122
42322222002230010231
511240430324432044
6232023340334325
720323425113021
oct2725202540455
9634281068618
10200421327149
1177aa868355a
1232a148443a5
1315b906b9c94
1499b4038381
15533044bdee
hex2eaa0ac12d

200421327149 has 2 divisors, whose sum is σ = 200421327150. Its totient is φ = 200421327148.

The previous prime is 200421327109. The next prime is 200421327151. The reversal of 200421327149 is 941723124002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 185687737225 + 14733589924 = 430915^2 + 121382^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200421327149 is a prime.

Together with 200421327151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200421327109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100210663574 + 100210663575.

It is an arithmetic number, because the mean of its divisors is an integer number (100210663575).

Almost surely, 2200421327149 is an apocalyptic number.

It is an amenable number.

200421327149 is a deficient number, since it is larger than the sum of its proper divisors (1).

200421327149 is an equidigital number, since it uses as much as digits as its factorization.

200421327149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 35.

The spelling of 200421327149 in words is "two hundred billion, four hundred twenty-one million, three hundred twenty-seven thousand, one hundred forty-nine".