Base | Representation |
---|---|
bin | 10010101110001000… |
… | …100010100010101111 |
3 | 1220212220020001021021 |
4 | 102232020202202233 |
5 | 312131420442112 |
6 | 13122345315011 |
7 | 1311062412505 |
oct | 225610424257 |
9 | 56786201237 |
10 | 20101343407 |
11 | 8585758902 |
12 | 3a8ba95a67 |
13 | 1b8469ba52 |
14 | d89946675 |
15 | 7c9ad8907 |
hex | 4ae2228af |
20101343407 has 2 divisors, whose sum is σ = 20101343408. Its totient is φ = 20101343406.
The previous prime is 20101343401. The next prime is 20101343413. The reversal of 20101343407 is 70434310102.
It is a balanced prime because it is at equal distance from previous prime (20101343401) and next prime (20101343413).
It is a cyclic number.
It is not a de Polignac number, because 20101343407 - 215 = 20101310639 is a prime.
It is a super-2 number, since 2×201013434072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20101343401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10050671703 + 10050671704.
It is an arithmetic number, because the mean of its divisors is an integer number (10050671704).
Almost surely, 220101343407 is an apocalyptic number.
20101343407 is a deficient number, since it is larger than the sum of its proper divisors (1).
20101343407 is an equidigital number, since it uses as much as digits as its factorization.
20101343407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 20101343407 its reverse (70434310102), we get a palindrome (90535653509).
The spelling of 20101343407 in words is "twenty billion, one hundred one million, three hundred forty-three thousand, four hundred seven".
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