Base | Representation |
---|---|
bin | 1001001001010010001111… |
… | …11001011100010000000101 |
3 | 2122012112001102100021011012 |
4 | 10210221013321130100011 |
5 | 10113441234214321013 |
6 | 110434303530452005 |
7 | 4143626400051245 |
oct | 444510771342005 |
9 | 78175042307135 |
10 | 20110243120133 |
11 | 6453784a71981 |
12 | 23095bb894005 |
13 | b2b506c849ba |
14 | 4d74ab849b25 |
15 | 24d1a84a41a8 |
hex | 124a47e5c405 |
20110243120133 has 2 divisors, whose sum is σ = 20110243120134. Its totient is φ = 20110243120132.
The previous prime is 20110243120127. The next prime is 20110243120139. The reversal of 20110243120133 is 33102134201102.
It is a balanced prime because it is at equal distance from previous prime (20110243120127) and next prime (20110243120139).
It can be written as a sum of positive squares in only one way, i.e., 14356687716484 + 5753555403649 = 3789022^2 + 2398657^2 .
It is a cyclic number.
It is not a de Polignac number, because 20110243120133 - 214 = 20110243103749 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20110243120099 and 20110243120108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20110243120139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055121560066 + 10055121560067.
It is an arithmetic number, because the mean of its divisors is an integer number (10055121560067).
Almost surely, 220110243120133 is an apocalyptic number.
It is an amenable number.
20110243120133 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110243120133 is an equidigital number, since it uses as much as digits as its factorization.
20110243120133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 20110243120133 its reverse (33102134201102), we get a palindrome (53212377321235).
The spelling of 20110243120133 in words is "twenty trillion, one hundred ten billion, two hundred forty-three million, one hundred twenty thousand, one hundred thirty-three".
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