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20110331131020 = 223251319643703459
BaseRepresentation
bin1001001001010010011010…
…01001001011010010001100
32122012112021112221200101200
410210221031021023102030
510113441424232143040
6110434320353105500
74143631516120614
oct444511511132214
978175245850350
1020110331131020
11645381a714849
122309625258290
13b2b51c28b450
144d74b93d9a44
1524d1b108b630
hex124a4d24b48c

20110331131020 has 288 divisors, whose sum is σ = 69258957331200. Its totient is φ = 4682396533248.

The previous prime is 20110331131013. The next prime is 20110331131057. The reversal of 20110331131020 is 2013113301102.

20110331131020 is a `hidden beast` number, since 2 + 0 + 1 + 1 + 0 + 331 + 1 + 310 + 20 = 666.

It is a super-3 number, since 3×201103311310203 (a number of 41 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 20110331130984 and 20110331131002.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 28236051 + ... + 28939509.

Almost surely, 220110331131020 is an apocalyptic number.

20110331131020 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20110331131020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (34629478665600).

20110331131020 is an abundant number, since it is smaller than the sum of its proper divisors (49148626200180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20110331131020 is a wasteful number, since it uses less digits than its factorization.

20110331131020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 704149 (or 704144 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 20110331131020 its reverse (2013113301102), we get a palindrome (22123444432122).

The spelling of 20110331131020 in words is "twenty trillion, one hundred ten billion, three hundred thirty-one million, one hundred thirty-one thousand, twenty".