Base | Representation |
---|---|
bin | 1001001001010100000011… |
… | …00010010000001101001011 |
3 | 2122012121112210220221121111 |
4 | 10210222001202100031023 |
5 | 10114000224242320021 |
6 | 110434543512551151 |
7 | 4143662351320003 |
oct | 444520142201513 |
9 | 78177483827544 |
10 | 20111210120011 |
11 | 64541308a622a |
12 | 230982b6b24b7 |
13 | b2b62c40948a |
14 | 4d7560047003 |
15 | 24d2133178e1 |
hex | 124a8189034b |
20111210120011 has 2 divisors, whose sum is σ = 20111210120012. Its totient is φ = 20111210120010.
The previous prime is 20111210120003. The next prime is 20111210120063. The reversal of 20111210120011 is 11002101211102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20111210120011 - 23 = 20111210120003 is a prime.
It is a super-2 number, since 2×201112101200112 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20111210119973 and 20111210120000.
It is not a weakly prime, because it can be changed into another prime (20111210150011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055605060005 + 10055605060006.
It is an arithmetic number, because the mean of its divisors is an integer number (10055605060006).
Almost surely, 220111210120011 is an apocalyptic number.
20111210120011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111210120011 is an equidigital number, since it uses as much as digits as its factorization.
20111210120011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 20111210120011 its reverse (11002101211102), we get a palindrome (31113311331113).
The spelling of 20111210120011 in words is "twenty trillion, one hundred eleven billion, two hundred ten million, one hundred twenty thousand, eleven".
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