Base | Representation |
---|---|
bin | 101101101110100100010001… |
… | …001000111110110001010101 |
3 | 222101002010120012200202010212 |
4 | 231232210101020332301111 |
5 | 202330010121041432013 |
6 | 1551421345420455205 |
7 | 60234605043464354 |
oct | 5556442110766125 |
9 | 871063505622125 |
10 | 201112131202133 |
11 | 590981a3099028 |
12 | 1a680a659aa505 |
13 | 882aa3c448668 |
14 | 3793c442dd99b |
15 | 183b5c4a7a6a8 |
hex | b6e91123ec55 |
201112131202133 has 4 divisors (see below), whose sum is σ = 205391112717120. Its totient is φ = 196833149687148.
The previous prime is 201112131202121. The next prime is 201112131202243. The reversal of 201112131202133 is 331202131211102.
It is a happy number.
201112131202133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 201112131202133 - 24 = 201112131202117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 201112131202099 and 201112131202108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201112131202033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2139490757423 + ... + 2139490757516.
It is an arithmetic number, because the mean of its divisors is an integer number (51347778179280).
Almost surely, 2201112131202133 is an apocalyptic number.
It is an amenable number.
201112131202133 is a deficient number, since it is larger than the sum of its proper divisors (4278981514987).
201112131202133 is an equidigital number, since it uses as much as digits as its factorization.
201112131202133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4278981514986.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 201112131202133 its reverse (331202131211102), we get a palindrome (532314262413235).
The spelling of 201112131202133 in words is "two hundred one trillion, one hundred twelve billion, one hundred thirty-one million, two hundred two thousand, one hundred thirty-three".
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