Base | Representation |
---|---|
bin | 11101010001000000001… |
… | …101111110101111101111 |
3 | 21010021001120001010121022 |
4 | 131101000031332233233 |
5 | 230422234224214411 |
6 | 4135521410124355 |
7 | 265204323543125 |
oct | 35210015765757 |
9 | 7107046033538 |
10 | 2011122101231 |
11 | 705a03aa6091 |
12 | 2859288806bb |
13 | 117856870169 |
14 | 6d4a5a65915 |
15 | 374a9639edb |
hex | 1d44037ebef |
2011122101231 has 2 divisors, whose sum is σ = 2011122101232. Its totient is φ = 2011122101230.
The previous prime is 2011122101213. The next prime is 2011122101273. The reversal of 2011122101231 is 1321012211102.
It is a happy number.
Together with previous prime (2011122101213) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011122101231 - 238 = 1736244194287 is a prime.
It is a super-2 number, since 2×20111221012312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011128101231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005561050615 + 1005561050616.
It is an arithmetic number, because the mean of its divisors is an integer number (1005561050616).
Almost surely, 22011122101231 is an apocalyptic number.
2011122101231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011122101231 is an equidigital number, since it uses as much as digits as its factorization.
2011122101231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 2011122101231 its reverse (1321012211102), we get a palindrome (3332134312333).
The spelling of 2011122101231 in words is "two trillion, eleven billion, one hundred twenty-two million, one hundred one thousand, two hundred thirty-one".
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