2011201301141 has 2 divisors, whose sum is σ = 2011201301142. Its totient is φ = 2011201301140.

The previous prime is 2011201301129. The next prime is 2011201301143. The reversal of 2011201301141 is 1411031021102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1931293884100 + 79907417041 = 1389710^2 + 282679^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2011201301141 is a prime.

It is a super-2 number, since 2×2011201301141² (a number of 25 digits) contains 22 as substring.

Together with 2011201301143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2011201301143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005600650570 + 1005600650571.

It is an arithmetic number, because the mean of its divisors is an integer number (1005600650571).

Almost surely, 2^{2011201301141} is an apocalyptic number.

It is an amenable number.

2011201301141 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011201301141 is an equidigital number, since it uses as much as digits as its factorization.

2011201301141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 2011201301141 its reverse (1411031021102), we get a palindrome (3422232322243).

The spelling of 2011201301141 in words is "two trillion, eleven billion, two hundred one million, three hundred one thousand, one hundred forty-one".