Base | Representation |
---|---|
bin | 1001001001010101111010… |
… | …10000001100101111010111 |
3 | 2122012201010122011202021021 |
4 | 10210222331100030233113 |
5 | 10114004302234121213 |
6 | 110435231143102011 |
7 | 4144026235323523 |
oct | 444527520145727 |
9 | 78181118152237 |
10 | 20112212020183 |
11 | 64545a53a76a8 |
12 | 2309a6b141907 |
13 | b2b75bb6050a |
14 | 4d761712ad83 |
15 | 24d271271d8d |
hex | 124abd40cbd7 |
20112212020183 has 2 divisors, whose sum is σ = 20112212020184. Its totient is φ = 20112212020182.
The previous prime is 20112212020177. The next prime is 20112212020249. The reversal of 20112212020183 is 38102021221102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20112212020183 - 29 = 20112212019671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20112212020123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056106010091 + 10056106010092.
It is an arithmetic number, because the mean of its divisors is an integer number (10056106010092).
Almost surely, 220112212020183 is an apocalyptic number.
20112212020183 is a deficient number, since it is larger than the sum of its proper divisors (1).
20112212020183 is an equidigital number, since it uses as much as digits as its factorization.
20112212020183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 20112212020183 its reverse (38102021221102), we get a palindrome (58214233241285).
The spelling of 20112212020183 in words is "twenty trillion, one hundred twelve billion, two hundred twelve million, twenty thousand, one hundred eighty-three".
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