Base | Representation |
---|---|
bin | 11101010001001011100… |
… | …010011011101101000111 |
3 | 21010021112210101121100022 |
4 | 131101023202123231013 |
5 | 230423131333341403 |
6 | 4135552312405355 |
7 | 265212121010132 |
oct | 35211342335507 |
9 | 7107483347308 |
10 | 2011312012103 |
11 | 705aa1217a19 |
12 | 2859803a685b |
13 | 117887004164 |
14 | 6d4c2d7d219 |
15 | 374bb14ed38 |
hex | 1d44b89bb47 |
2011312012103 has 2 divisors, whose sum is σ = 2011312012104. Its totient is φ = 2011312012102.
The previous prime is 2011312012081. The next prime is 2011312012141. The reversal of 2011312012103 is 3012102131102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011312012103 - 28 = 2011312011847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011312012163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005656006051 + 1005656006052.
It is an arithmetic number, because the mean of its divisors is an integer number (1005656006052).
Almost surely, 22011312012103 is an apocalyptic number.
2011312012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011312012103 is an equidigital number, since it uses as much as digits as its factorization.
2011312012103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 2011312012103 its reverse (3012102131102), we get a palindrome (5023414143205).
The spelling of 2011312012103 in words is "two trillion, eleven billion, three hundred twelve million, twelve thousand, one hundred three".
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