Base | Representation |
---|---|
bin | 11101010001110101001… |
… | …001001010101111100111 |
3 | 21010100100102211200202220 |
4 | 131101311021022233213 |
5 | 230431044032011403 |
6 | 4140145445403423 |
7 | 265235325043641 |
oct | 35216511125747 |
9 | 7110312750686 |
10 | 2012010032103 |
11 | 70631a234755 |
12 | 285b36109573 |
13 | 1179687cc246 |
14 | 6d54b95d891 |
15 | 3750c580953 |
hex | 1d47524abe7 |
2012010032103 has 4 divisors (see below), whose sum is σ = 2682680042808. Its totient is φ = 1341340021400.
The previous prime is 2012010032069. The next prime is 2012010032119. The reversal of 2012010032103 is 3012300102102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2012010032103 - 220 = 2012008983527 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2012010032143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335335005348 + ... + 335335005353.
It is an arithmetic number, because the mean of its divisors is an integer number (670670010702).
Almost surely, 22012010032103 is an apocalyptic number.
2012010032103 is a deficient number, since it is larger than the sum of its proper divisors (670670010705).
2012010032103 is an equidigital number, since it uses as much as digits as its factorization.
2012010032103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 670670010704.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 2012010032103 its reverse (3012300102102), we get a palindrome (5024310134205).
The spelling of 2012010032103 in words is "two trillion, twelve billion, ten million, thirty-two thousand, one hundred three".
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