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2012012112140 = 225100600605607
BaseRepresentation
bin11101010001110101010…
…001000110100100001100
321010100100120202101001022
4131101311101012210030
5230431100100042030
64140150002133312
7265235351526122
oct35216521064414
97110316671038
102012012112140
11706320425498
12285b36951238
13117969079c34
146d54bd41912
153750c841de5
hex1d47544690c

2012012112140 has 12 divisors (see below), whose sum is σ = 4225225435536. Its totient is φ = 804804844848.

The previous prime is 2012012112133. The next prime is 2012012112161. The reversal of 2012012112140 is 412112102102.

It is a super-3 number, since 3×20120121121403 (a number of 38 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50300302784 + ... + 50300302823.

It is an arithmetic number, because the mean of its divisors is an integer number (352102119628).

Almost surely, 22012012112140 is an apocalyptic number.

2012012112140 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2012012112140 is an abundant number, since it is smaller than the sum of its proper divisors (2213213323396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2012012112140 is a wasteful number, since it uses less digits than its factorization.

2012012112140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100600605616 (or 100600605614 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 2012012112140 its reverse (412112102102), we get a palindrome (2424124214242).

The spelling of 2012012112140 in words is "two trillion, twelve billion, twelve million, one hundred twelve thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 100600605607 201201211214 402402422428 503003028035 1006006056070 2012012112140