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2012031143315 = 5402406228663
BaseRepresentation
bin11101010001110110011…
…001101100110110010011
321010100101220120020220122
4131101312121230312103
5230431114433041230
64140151522100455
7265236002351444
oct35216631546623
97110356506818
102012031143315
11706330143936
12285b411aa72b
1311796ccb139b
146d5506972cb
153750e350be5
hex1d47666cd93

2012031143315 has 4 divisors (see below), whose sum is σ = 2414437371984. Its totient is φ = 1609624914648.

The previous prime is 2012031143209. The next prime is 2012031143323. The reversal of 2012031143315 is 5133411302102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2012031143315 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201203114327 + ... + 201203114336.

It is an arithmetic number, because the mean of its divisors is an integer number (603609342996).

Almost surely, 22012031143315 is an apocalyptic number.

2012031143315 is a deficient number, since it is larger than the sum of its proper divisors (402406228669).

2012031143315 is an equidigital number, since it uses as much as digits as its factorization.

2012031143315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402406228668.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 2012031143315 its reverse (5133411302102), we get a palindrome (7145442445417).

The spelling of 2012031143315 in words is "two trillion, twelve billion, thirty-one million, one hundred forty-three thousand, three hundred fifteen".

Divisors: 1 5 402406228663 2012031143315