Base | Representation |
---|---|
bin | 1001001001100110010010… |
… | …01011101111000000100011 |
3 | 2122020112211020021122000211 |
4 | 10210303021023233000203 |
5 | 10114130303020023021 |
6 | 110443243305154551 |
7 | 4144460122006504 |
oct | 444631113570043 |
9 | 78215736248024 |
10 | 20121002111011 |
11 | 64582a6157a7a |
12 | 230b702a8ba57 |
13 | b2c52cc970a9 |
14 | 4d7c0c700bab |
15 | 24d5d7cd83e1 |
hex | 124cc92ef023 |
20121002111011 has 2 divisors, whose sum is σ = 20121002111012. Its totient is φ = 20121002111010.
The previous prime is 20121002110999. The next prime is 20121002111047. The reversal of 20121002111011 is 11011120012102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20121002111011 - 239 = 19571246297123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20121002110982 and 20121002111000.
It is not a weakly prime, because it can be changed into another prime (20121002111311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10060501055505 + 10060501055506.
It is an arithmetic number, because the mean of its divisors is an integer number (10060501055506).
Almost surely, 220121002111011 is an apocalyptic number.
20121002111011 is a deficient number, since it is larger than the sum of its proper divisors (1).
20121002111011 is an equidigital number, since it uses as much as digits as its factorization.
20121002111011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 20121002111011 its reverse (11011120012102), we get a palindrome (31132122123113).
The spelling of 20121002111011 in words is "twenty trillion, one hundred twenty-one billion, two million, one hundred eleven thousand, eleven".
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